我正在尝试将 xml 解析为 java 对象，我已阅读并实现了以下教程:

http://www.vogella.com/articles/JAXB/article.html (完美运行)

但是当我创建自己的类时(类似于教程中的类)

我得到:线程“主”com.sun.xml.internal.bind.v2.runtime.IllegalAnnotationsException 中的异常:1 次 IllegalAnnotationExceptions 类有两个同名属性“clienteList”

除非我在 Clientes 类上使用 @XmlAccessorType(XmlAccessType.FIELD) 但在教程中未被使用。

有什么想法吗？

(它与 @XmlAccessorType(XmlAccessType.FIELD) 注释一起工作正常，但我想知道为什么我的类需要它，而教程中的类不需要它)

提前感谢您提供任何信息。

类客户

package mx.com.findep.crediseguros.dto.servicios.finsol;

import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name = "cliente")
public class Cliente {

  private String numeroPersona;

  @XmlElement(name = "numeroPersona")
  public String getNumeroPersona() {
    return numeroPersona;
  }

  public void setNumeroPersona(String numeroPersona) {
    this.numeroPersona = numeroPersona;
  }

} 

类客户

package mx.com.findep.crediseguros.dto.servicios.finsol;

import java.util.ArrayList;

import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name = "clientes")
//@XmlAccessorType(XmlAccessType.FIELD) //without this line it fails
public class Clientes {

      // XmLElementWrapper generates a wrapper element around XML representation
      @XmlElementWrapper(name = "clienteList")
      // XmlElement sets the name of the entities
      @XmlElement(name = "cliente")
      private ArrayList<Cliente> clienteList;


      public void setClienteList(ArrayList<Cliente> clienteList) {
        this.clienteList = clienteList;
      }

      public ArrayList<Cliente> getClienteList() {
        return clienteList;
      }


    }

测试我的编码

package mx.com.findep.crediseguros.dto.servicios.finsol;

import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;


public class TestClientesXml {

  private static final String SOME_XML = "C:/bea/user_projects/domains/DominioDesarrollo/esquemas/calculoCostoSeguroPeticion.xml";

  public static void main(String[] args) throws JAXBException, IOException {

    ArrayList<Cliente> clienteList = new ArrayList<Cliente>();

    Cliente cliente1 = new Cliente();
    cliente1.setNumeroPersona("1");

    clienteList.add(cliente1);

    Cliente cliente2 = new Cliente();
    cliente2.setNumeroPersona("2");
    clienteList.add(cliente2);

    Clientes clientes = new Clientes();

    clientes.setClienteList(clienteList);

    JAXBContext context = JAXBContext.newInstance(Clientes.class);
    Marshaller m = context.createMarshaller();
    m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);

    m.marshal(clientes, System.out);

    m.marshal(clientes, new File(SOME_XML));

    System.out.println();
    System.out.println("Output from our XML File: ");
    Unmarshaller um = context.createUnmarshaller();
    Clientes clientes2 = (Clientes) um.unmarshal(new FileReader(SOME_XML));
    ArrayList<Cliente> list = clientes2.getClienteList();
    for (Cliente cliente : list) {
      System.out.println("Cliente: " + cliente.getNumeroPersona());
    }
  }
} 

最佳答案

默认情况下，JAXB 将公共(public)字段和属性视为已映射。如果您注释一个字段，它会认为该字段和属性已映射，从而导致冲突。如果没有 @XmlAccessorType(XmlAccessType.FIELD)，您应该注释 get 或 set 方法。

了解更多信息

• http://blog.bdoughan.com/2011/06/using-jaxbs-xmlaccessortype-to.html

关于java jaxb简单解析需要@XmlAccessorType(XmlAccessType.FIELD)注解，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/19821896/