@Override
      public int compareTo(final myRow another) {

        final int BEFORE    =-1;
        final int EQUAL     = 0;
        final int AFTER     = 1;

        if (this==another) return EQUAL;

        if (sorttype==sort_type.SORT_ABC) {

            int rv      =0;
            int sorted  =row.toLowerCase().compareTo(another.getRow().toLowerCase());

            if (this.getUserType()==user_type.USER_TYPE_BANNED) rv=AFTER;
            if (this.getUserType()==user_type.USER_TYPE_NORMAL) rv=sorted;
            if (this.getUserType()==user_type.USER_TYPE_FRIEND) rv=BEFORE;

            Log.e("sorted", row+" "+this.getUserType()+" - "+rv+" ");

            return rv;

        } else if (sorttype==sort_type.SORT_LOGINTIME) {

            if (this.getUserType()==user_type.USER_TYPE_BANNED) {
                return AFTER;
            }
            if (this.getUserType()==user_type.USER_TYPE_NORMAL) return EQUAL;
            if (this.getUserType()==user_type.USER_TYPE_FRIEND) {
                //int sorted    =row.toLowerCase().compareTo(another.getRow().toLowerCase());
                return BEFORE;
            }

            //return 0;
        }

        return 0;

        //return row.toLowerCase().compareTo(another.getRow().toLowerCase());
      }

我有一个带有昵称的字符串用户列表。我已经禁止用户，普通用户和 friend 用户。

我想将我的好友用户排序到列表的顶部，将被禁止的用户排序到列表的底部，我想以 ASC 样式显示他们。

我该怎么做？

所以结构是:

Abc  (friend)
abrt (friend)
dfgh (friend)

abdfg (normal user)
bnmm  (normal user)
wert  (normal user)

Andgh  (banned user)
Dfghhj (banned user)
Qwer   (banned user)

我明白了:

06-19 14:43:46.586: ERROR/AndroidRuntime(23434): java.lang.IllegalArgumentException: Comparison method violates its general contract!

最佳答案

您的代码看起来有点复杂。最简单的方法是从最高优先级的字段开始，然后向下移动到其他字段。一个示例代码是:

public class Member implements Comparable<Member> {

    static enum Status {
        NORMAL(1), FRIEND(2), BANNED(3);

        private final int order;

        Status(int order) {
            this.order = order;
        }

        public int getOrder() {
            return this.order;
        }

    };

    private final String name;

    private final Status status;

    public Member(final String name, final Status status) {
        this.name = name;
        this.status = status;
    }

    @Override
    public int compareTo(Member o) {
        if (this.status.equals(o.status)) {
            return this.name.compareTo(o.name);
        } else {
            return this.status.compareTo(o.status);
        }
    }

    @Override
    public String toString() {
        return "Member [name=" + name + ", status=" + status + "]";
    }

    public static void main(String[] args) throws Throwable {
        Member[] members = {
                        new Member("abrt", Status.FRIEND),
                        new Member("dfgh", Status.FRIEND),
                        new Member("abdf", Status.NORMAL),
                        new Member("wert", Status.NORMAL),
                        new Member("andgh", Status.BANNED),
                        new Member("qwer", Status.BANNED)
        };
        List<Member> lst = Arrays.asList(members);
        Collections.sort(lst);
        System.out.println(lst);
    }


}

关于java - 使用 Comparable 的 Android java 自定义排序，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6402456/