实际上,当我的设备中有链接应用程序时,我已经完成了链接集成。我需要在没有 Linked in app 的情况下执行相同的操作。可以像 Facebook 一样进行身份验证。
最佳答案
尝试使用以下代码在浏览器中使用 LinkedIn 登录
public class LinkedInActivity extends AppCompatActivity {
private String TAG=LinkedInActivity.class.getSimpleName();
public static final String LINKED_IN_PEOPLE_PROFILE = "https://api.linkedin.com/v1/people/~:(id,first-name,last-name,email-address,picture-url)?format=json"; // specific basic details
private static final String API_KEY = "Your Client Key";
//This is the private api key of our application
private static final String SECRET_KEY = "Your Client Secret Key";
//This is any string of your choice we can use.
private static final String STATE = "My String value";
//This is the url that LinkedIn Auth 2.0 process will redirect to. We can put whatever we want that starts with http:// or https:// .
//We use a made up url that we will intercept when redirecting. Avoid Uppercases.
private static final String REDIRECT_URI = "Your OAuth 2.0 redirect URL in";
private String accessToken="";
//These are constants used for build the urls
private static final String AUTHORIZATION_URL = "https://www.linkedin.com/uas/oauth2/authorization";
private static final String ACCESS_TOKEN_URL = "https://www.linkedin.com/uas/oauth2/accessToken";
private static final String SECRET_KEY_PARAM = "client_secret";
private static final String RESPONSE_TYPE_PARAM = "response_type";
private static final String GRANT_TYPE_PARAM = "grant_type";
private static final String GRANT_TYPE = "authorization_code";
private static final String RESPONSE_TYPE_VALUE ="code";
private static final String CLIENT_ID_PARAM = "client_id";
private static final String STATE_PARAM = "state";
private static final String REDIRECT_URI_PARAM = "redirect_uri";
/*---------------------------------------*/
private static final String QUESTION_MARK = "?";
private static final String AMPERSAND = "&";
private static final String EQUALS = "=";
private WebView webView, webView1;
private ProgressDialog pd;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_linked_in);
//get the webView from the layout
webView = (WebView) findViewById(R.id.main_activity_web_view);
//Request focus for the webview
webView.requestFocus(View.FOCUS_DOWN);
//Show a progress dialog to the user
pd = ProgressDialog.show(this, "", "Loading...", true);
//Set a custom web view client
webView.setWebViewClient(new WebViewClient(){
@Override
public void onPageStarted(WebView view, String authorizationUrl, Bitmap favicon) {
}
@Override
public void onPageFinished(WebView view, String url) {
if (pd != null && pd.isShowing()) {
pd.dismiss();
}
}
@Override
public boolean shouldOverrideUrlLoading(WebView view, String authorizationUrl){
if (authorizationUrl.startsWith(REDIRECT_URI)) {
Log.i("Authorize", "");
Uri uri = Uri.parse(authorizationUrl);
//We take from the url the authorizationToken and the state token. We have to check that the state token returned by the Service is the same we sent.
//If not, that means the request may be a result of CSRF and must be rejected.
String stateToken = uri.getQueryParameter(STATE_PARAM);
if (stateToken == null || !stateToken.equals(STATE)) {
Log.e("Authorize", "State token doesn't match");
return true;
}
//If the user doesn't allow authorization to our application, the authorizationToken Will be null.
String authorizationToken = uri.getQueryParameter(RESPONSE_TYPE_VALUE);
if (authorizationToken == null) {
Log.i("Authorize", "The user doesn't allow authorization.");
return true;
}
Log.i("Authorize", "Auth token received: " + authorizationToken);
//Generate URL for requesting Access Token
String accessTokenUrl = getAccessTokenUrl(authorizationToken);
//We make the request in a AsyncTask
new PostRequestAsyncTask().execute(accessTokenUrl);
} else {
//Default behaviour
Log.i("Authorize", "Redirecting to: " + authorizationUrl);
webView.loadUrl(authorizationUrl);
}
return true;
}
});
//Get the authorization Url
String authUrl = getAuthorizationUrl();
Log.i("Authorize", "Loading Auth Url: " + authUrl);
//Load the authorization URL into the webView
webView.loadUrl(authUrl);
}
/**
* Method that generates the url for get the access token from the Service
* @return Url
*/
private static String getAccessTokenUrl(String authorizationToken){
return ACCESS_TOKEN_URL
+QUESTION_MARK
+GRANT_TYPE_PARAM+EQUALS+GRANT_TYPE
+AMPERSAND
+RESPONSE_TYPE_VALUE+EQUALS+authorizationToken
+AMPERSAND
+CLIENT_ID_PARAM+EQUALS+API_KEY
+AMPERSAND
+REDIRECT_URI_PARAM+EQUALS+REDIRECT_URI
+AMPERSAND
+SECRET_KEY_PARAM+EQUALS+SECRET_KEY;
}
/**
* Method that generates the url for get the authorization token from the Service
* @return Url
*/
private static String getAuthorizationUrl(){
return AUTHORIZATION_URL
+QUESTION_MARK+RESPONSE_TYPE_PARAM+EQUALS+RESPONSE_TYPE_VALUE
+AMPERSAND+CLIENT_ID_PARAM+EQUALS+API_KEY
+AMPERSAND+STATE_PARAM+EQUALS+STATE
+AMPERSAND+REDIRECT_URI_PARAM+EQUALS+REDIRECT_URI;
}
private class PostRequestAsyncTask extends AsyncTask<String, Void, Boolean> {
@Override
protected void onPreExecute(){
pd = ProgressDialog.show(LinkedInActivity.this, "", "Loading...",true);
}
@Override
protected Boolean doInBackground(String... urls) {
if(urls.length>0){
String url = urls[0];
URL sourceUrl = null;
try {
sourceUrl = new URL(url);
} catch (MalformedURLException e) {
e.printStackTrace();
}
try{
HttpURLConnection conn = (HttpURLConnection)sourceUrl.openConnection();
conn.setReadTimeout(10000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("GET");
conn.setDoInput(true);
conn.connect();
int responsecode = conn.getResponseCode();
Log.d(TAG, "Response Code is :"+responsecode);
if(responsecode == 200){
String result = "", line = "";
InputStream inputStream = conn.getInputStream();
BufferedReader br = new BufferedReader(new InputStreamReader(inputStream));
while((line=br.readLine())!=null)
{
result = result+line;
}
//Convert the string result to a JSON Object
JSONObject resultJson = new JSONObject(result);
//Extract data from JSON Response
int expiresIn = resultJson.has("expires_in") ? resultJson.getInt("expires_in") : 0;
accessToken = resultJson.has("access_token") ? resultJson.getString("access_token") : null;
Log.e("Tokenm", ""+accessToken);
if(expiresIn>0 && accessToken!=null){
Log.i("Authorize", "This is the access Token: "+accessToken+". It will expires in "+expiresIn+" secs");
//Calculate date of expiration
Calendar calendar = Calendar.getInstance();
calendar.add(Calendar.SECOND, expiresIn);
long expireDate = calendar.getTimeInMillis();
return true;
}
}
}catch(IOException e){
Log.e("Authorize","Error Http response "+e.getLocalizedMessage());
}
catch (ParseException e) {
Log.e("Authorize","Error Parsing Http response "+e.getLocalizedMessage());
} catch (JSONException e) {
Log.e("Authorize","Error Parsing Http response "+e.getLocalizedMessage());
}
}
return false;
}
@Override
protected void onPostExecute(Boolean status){
if(pd!=null && pd.isShowing()){
pd.dismiss();
}
if(status)
{
Log.e(TAG, "Access Token : "+ accessToken);
}
}
};
}
*
activity_linked_in.xml
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">
<WebView
android:id="@+id/main_activity_web_view"
android:layout_width="match_parent"
android:layout_height="match_parent" />
</RelativeLayout>
关于android - 没有 Android Linkedin App 的 Android 中的 Linkedin 集成,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37459969/
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