这是一段用户邀请码。该代码应从之前的 POST 表单中获取电子邮件地址，然后检查其格式是否正确。我使用了一个名为 checkMail 的函数来完成这项工作。但是，似乎每当电子邮件格式错误或表单留空时，它都不会显示此行:

else if(checkEmail($_POST['email'])==false){ 'Whoops! Looks like the email address you selected is invalid :('; }

或

else { 'Whoops! It looks like you didn't actually add an email address...'; }

被困了几个小时，试图调试...希望这里有人能帮助我!!

完整代码如下:

if(!empty($_POST['email'])) {
        if(checkEmail($_POST['email'])==true) {
            $thisDomain = str_replace('www.', '', $_SERVER['HTTP_HOST']);
            $mailcont = "Someone has invited you to an invite only website!\nYour invite code is: ".$_POST['code'].".\n\nYou can use it at http://".$thisDomain."?go=register&hash=".$_POST['code'];
            if(sendEmail($_POST['email'],'You have been invited!',$mailcont,'noreply@'.$thisDomain)) {
                echo 'Your invite was dispatched to '.$_POST['email'].'<br /><br />Go back <a href="?go=home">home</a>';
            } else { echo 'Whoops! Something went horribly wrong, and we couldn&#39;t send the email :('; }
        } else if(checkEmail($_POST['email'])==false){ 'Whoops! Looks like the email address you selected is invalid :('; }
    } else { 'Whoops! It looks like you didn&#39;t actually add an email address...'; }
break;

这是函数 checkMail 的代码:

function checkEmail($email) 
   /**
Validate an email address.
Provide email address (raw input)
Returns true if the email address has the email 
address format and the domain exists.
*/
{
   $isValid = true;
   $atIndex = strrpos($email, "@");
   if (is_bool($atIndex) && !$atIndex)
   {
      $isValid = false;
   }
   else
   {
      $domain = substr($email, $atIndex+1);
      $local = substr($email, 0, $atIndex);
      $localLen = strlen($local);
      $domainLen = strlen($domain);
      if ($localLen < 1 || $localLen > 64)
      {
         // local part length exceeded
         $isValid = false;
      }
      else if ($domainLen < 1 || $domainLen > 255)
      {
         // domain part length exceeded
         $isValid = false;
      }
      else if ($local[0] == '.' || $local[$localLen-1] == '.')
      {
         // local part starts or ends with '.'
         $isValid = false;
      }
      else if (preg_match('/\\.\\./', $local))
      {
         // local part has two consecutive dots
         $isValid = false;
      }
      else if (!preg_match('/^[A-Za-z0-9\\-\\.]+$/', $domain))
      {
         // character not valid in domain part
         $isValid = false;
      }
      else if (preg_match('/\\.\\./', $domain))
      {
         // domain part has two consecutive dots
         $isValid = false;
      }
      else if
(!preg_match('/^(\\\\.|[A-Za-z0-9!#%&`_=\\/$\'*+?^{}|~.-])+$/',
                 str_replace("\\\\","",$local)))
      {
         // character not valid in local part unless 
         // local part is quoted
         if (!preg_match('/^"(\\\\"|[^"])+"$/',
             str_replace("\\\\","",$local)))
         {
            $isValid = false;
         }
      }
      if ($isValid && !(checkdnsrr($domain,"MX") || 
 checkdnsrr($domain,"A")))
      {
         // domain not found in DNS
         $isValid = false;
      }
   }
   return $isValid;
}

提前谢谢大家。你们太棒了，我是 stackoverflow 的新手，但我发现自己每天都会回到这里寻求想法和社区的大力帮助!

最佳答案

else { '哎呀!看起来你实际上并没有添加电子邮件地址......'; 应该 else { echo '哎呀!看起来你实际上并没有添加电子邮件地址......'; }

关于php - 验证电子邮件格式 PHP，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/11266967/