我正在基于过去五次观察的相对值在 MySQL 中构建标准化数据集。为此，我需要知道过去五个数据点的最大值和最小值是多少。我正在处理一个子选择，其工作方式如下:

我需要获取表中前五次出现的最小值和最大值。虽然我的表当前按 DESC 顺序排列，但我不能依赖它来维护该结构，因为特定 MY_ID 的 RECENT_DATE 的后续更新将更改最近的 5 个，同时更新 MY_VALUE。

这是我正在处理的一些基本表。

    MY_ID | RECENT_DATE | MY_VALUE
    392, 2013-10-06 12:00:00, 18332
    146, 2013-09-06 12:00:00, 5623
    72, 2013-09-02 12:00:00, 23242
    643, 2013-09-01 12:00:00, 15242
    492, 2013-08-06 12:00:00, 15332
    346, 2013-07-26 12:00:00, 17332
    172, 2013-07-22 12:00:00, 14001
    123, 2013-07-22 12:00:00, 13918
    243, 2013-07-11 12:00:00, 23229

最后我需要它看起来像。

    MY_ID | RECENT_DATE | MY_VALUE | MAX_VALUE | MIN_VALUE
    392, 2013-10-06 12:00:00, 18332, 23242, 5623
    146, 2013-09-06 12:00:00, 5623, 23242, 5623
    72, 2013-09-02 12:00:00, 23242, 23242, 14001
    643, 2013-09-01 12:00:00, 15242, 17332, 13918
    492, 2013-08-06 12:00:00, 15332, 23229, 13918
    346, 2013-07-26 12:00:00, 17332, 23229, 13918
    172, 2013-07-22 12:00:00, 14001, 23229, 13918
    123, 2013-07-22 12:00:00, 13918, 23229, 13918
    243, 2013-07-11 12:00:00, 23229, 23229, 23229

所以这是一个快速示例表

CREATE TABLE IF NOT EXISTS dbo.baseTable
(
    MY_ID BIGINT(20) UNSIGNED, 
    RECENT_DATE DATETIME, 
    MY_VALUE BIGINT(20), 
);

INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (392, '2013-10-06 12:00:00', 18332);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (146, '2013-09-06 12:00:00', 5623);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (72, '2013-09-02 12:00:00', 23242);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (643, '2013-09-01 12:00:00', 15242);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (492, '2013-08-06 12:00:00', 15332);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (346, '2013-07-26 12:00:00', 17332);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (172, '2013-07-22 12:00:00', 14001);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (123, '2013-07-22 12:00:00', 13918);
INSERT INTO dbo.baseTable (MY_ID, RECENT_DATE, MY_VALUE) VALUES (243, '2013-07-11 12:00:00', 23229);

现在这是我被屠杀的查询尝试 A:

SELECT DISTINCT t1.MY_ID,
        t1.RECENT_DATE,
        t1.MY_VALUE, MAX(t2.MY_VALUE) AS MAX_MY_VALUE, MIN(t2.MY_VALUE) AS MIN_MY_VALUE
FROM dbo.baseTable t1
    INNER JOIN (
        SELECT t.MY_ID, t1.RECENT_DATE, t.MY_VALUE
            FROM dbo.baseTable t
            WHERE t.RECENT_DATE <= t1.RECENT_DATE
            LIMIT 5) AS t2 ON t1.MY_ID = t2.MY_ID
/* WHERE OMITTED */
ORDER BY t1.RECENT_DATE DESC
;

最佳答案

此查询应返回您需要的结果:

SELECT
  ta.MY_ID, ta.MY_ID, ta.RECENT_DATE, ta.MY_VALUE,
  MAX(tb.MY_VALUE),
  MIN(tb.MY_VALUE)
FROM (
  SELECT
    t1.MY_ID,
    t1.RECENT_DATE,
    t1.MY_VALUE,
    SUBSTRING_INDEX(GROUP_CONCAT(t2.MY_ID ORDER BY t2.RECENT_DATE DESC), ',', 5) as Last_5
  FROM
    baseTable t1 INNER JOIN baseTable t2
    ON t1.recent_date >= t2.recent_date
  GROUP BY
    t1.my_id
) ta INNER JOIN baseTable tb ON FIND_IN_SET(tb.MY_ID, Last_5)
GROUP BY
  ta.MY_ID
ORDER BY
  RECENT_DATE DESC

它不是标准的 SQL，并使用了一些 MySQL 技巧。 请看 fiddle here .

关于MySQL:使用子选择计算本地化的 MIN MAX，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/21892221/