我正试图掌握 Java 应用程序的内部化，如图所示 here .我不能。我创建了一个扩展 ListResourceBundle 的类，并尝试检索 key 。不过，我一直有异常(exception)。如果您查看教程，它说要使用 .class 文件。这不可能是对的，对吗？

[项目树]

[源代码]

这是我正在使用的两个类，只是 MainWindow_xx_XX.java 文件中的一个，因为它们基本相同。 首先是 ListResourceBundle:

public class MainWindow_en_US extends ListResourceBundle {

    @Override
    protected Object[][] getContents() {
        return contents;
    }
    private Object[][] contents = {
        {"fileLabel", "File"},
        {"newSessionLabel", "New session..."},
        {"openSessionLabel", "Open session..."},
        {"saveLabel", "Save"},
        {"exitLabel", "Exit"},
        {"editLabel", "Edit"},
        {"toolsLabel", "Tools"},
        {"helpLabel", "Help"}
    };
}

现在是我用来加载它的方法:

    private static final int DEFAULT_LOCALE = 0;
    private ResourceBundle bundle;
    public static Locale locale;
    public static final Locale[] supportedLocales = {
        new Locale("en", "US"),
        new Locale("es", "ES")
    };

public MainWindow() {
    for (Locale i : supportedLocales) {
        if (i.getLanguage().equals(Locale.getDefault().getLanguage())) {
            locale = i;
            break;
        } else {
            locale = supportedLocales[DEFAULT_LOCALE];
        }
    }
    bundle = ResourceBundle.getBundle("MainWindow", locale); //EXCEPTION POINTS HERE!!!
    initComponents();
}

我不断收到以下异常。我知道我可以通过属性文件来完成它，但它让我无法理解，因为我无法使用 Oracle 极其简单的教程。

Exception in thread "AWT-EventQueue-0" java.util.MissingResourceException: Can't find bundle for base name MainWindow, locale es_ES
    at java.util.ResourceBundle.throwMissingResourceException(ResourceBundle.java:1499)
    at java.util.ResourceBundle.getBundleImpl(ResourceBundle.java:1322)
    at java.util.ResourceBundle.getBundle(ResourceBundle.java:796)
    at -.-.-.-.-.<init>(MainWindow.java:37)
    at -.-.-.-.MainWindow$2.run(MainWindow.java:145)
    at java.awt.event.InvocationEvent.dispatch(InvocationEvent.java:251)
    at java.awt.EventQueue.dispatchEventImpl(EventQueue.java:701)
    at java.awt.EventQueue.access$000(EventQueue.java:102)
    at java.awt.EventQueue$3.run(EventQueue.java:662)
    at java.awt.EventQueue$3.run(EventQueue.java:660)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.security.ProtectionDomain$1.doIntersectionPrivilege(ProtectionDomain.java:76)
    at java.awt.EventQueue.dispatchEvent(EventQueue.java:671)
    at java.awt.EventDispatchThread.pumpOneEventForFilters(EventDispatchThread.java:244)
    at java.awt.EventDispatchThread.pumpEventsForFilter(EventDispatchThread.java:163)
    at java.awt.EventDispatchThread.pumpEventsForHierarchy(EventDispatchThread.java:151)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:147)
    at java.awt.EventDispatchThread.pumpEvents(EventDispatchThread.java:139)
    at java.awt.EventDispatchThread.run(EventDispatchThread.java:97)

最佳答案

您需要使用完全限定的基本名称:

bundle = ResourceBundle.getBundle("pkg.subpkg.resources.MainWindow", locale);

关于java - 如何使用 ResourceBundle，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14464153/