当我的用户在我的 UISearchBar 中搜索一个项目时，如果输入栏中的完整单词与其中一个结果匹配，则会显示结果。 例如 如果输入“Panda”，Panda 将在 tableView 结果中弹出。但是，如果输入“Pan”，则不会显示任何结果。如何让我的搜索结果过滤器在用户输入时起作用？即使只输入“pan”也应该显示 Panda。

我的过滤器代码目前看起来像这样:

.m

- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
{
    NSPredicate *resultPredicate = [NSPredicate
                                    predicateWithFormat:@"SELF contains[cd] %@",
                                    searchText];

    searchResults = [self.neighbourData filteredArrayUsingPredicate:resultPredicate];
}

/*
-(BOOL)searchDisplayController:(UISearchDisplayController *)controller
shouldReloadTableForSearchString:(NSString *)searchString
{
    [self filterContentForSearchText:searchString
                               scope:[[self.searchDisplayController.searchBar scopeButtonTitles]
                                      objectAtIndex:[self.searchDisplayController.searchBar
                                                     selectedScopeButtonIndex]]];

    return YES;
} */


- (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView
{
    // Return the number of sections.
    return 1;
}

- (NSInteger) tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section
{

    if (tableView == self.searchDisplayController.searchResultsTableView) {
        return [searchResults count];

    } else { 

    return [self.neighbourData count];

    }
}

- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath
{

    static NSString *NetworkTableIdentifier = @"sidebarCell";

    self.tableView.separatorStyle = UITableViewCellSeparatorStyleNone;

    sidebarCell *cell = (sidebarCell *)[tableView dequeueReusableCellWithIdentifier:NetworkTableIdentifier];
    if (cell == nil)

    {



        NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"sidebarCell" owner:self options:nil];
        cell = [nib objectAtIndex:0];
    }

    if (tableView == self.searchDisplayController.searchResultsTableView) {



        NSDictionary *userName = [searchResults objectAtIndex:indexPath.row];
        [[cell username] setText:[userName objectForKey:@"first name"]];

        NSDictionary *userlast = [searchResults objectAtIndex:indexPath.row];
        [[cell lastName] setText:[userlast objectForKey:@"last name"]];

        NSDictionary *userBio = [searchResults objectAtIndex:indexPath.row];
        [[cell userDescription] setText:[userBio objectForKey:@"userbio"]];



        NSString *profilePath = [[searchResults objectAtIndex:indexPath.row] objectForKey:@"photo_path"];

        [cell.usermini sd_setImageWithURL:[NSURL URLWithString:profilePath]];

        NSLog(@"This is profilePath %@",profilePath);



    } else {

    NSDictionary *userName = [self.neighbourData objectAtIndex:indexPath.row];
    [[cell username] setText:[userName objectForKey:@"first name"]];

    NSDictionary *userlast = [self.neighbourData objectAtIndex:indexPath.row];
    [[cell lastName] setText:[userlast objectForKey:@"last name"]];

    NSDictionary *userBio = [self.neighbourData objectAtIndex:indexPath.row];
    [[cell userDescription] setText:[userBio objectForKey:@"userbio"]];



    NSString *profilePath = [[self.neighbourData objectAtIndex:indexPath.row] objectForKey:@"photo_path"];

    [cell.usermini sd_setImageWithURL:[NSURL URLWithString:profilePath]];

    NSLog(@"This is profilePath %@",profilePath);




    }
    return cell;

}


- (CGFloat)tableView:(UITableView *)tableView heightForRowAtIndexPath:(NSIndexPath *)indexPath
{
    return 115;
}

邻居数据日志:

[12663:3559832] This is the neighbourdata (
        {
        address = "1144 fake street";
        city = Las Vegas;
        "first name" = Panda;
        "last name" = Zoo;
        "photo_path" = "none";
      }

最佳答案

试试这个

- (void)searchBar:(UISearchBar *)searchBar textDidChange:(NSString *)searchText
    {
       NSPredicate * predicate =[NSPredicate predicateWithFormat:@"%K contains[cd] %@",@"first name", searchText];
       searchResults = [self.neighbourData filteredArrayUsingPredicate:resultPredicate];
     if searchResults.count == 0
     {
        NSPredicate * predicate =[NSPredicate predicateWithFormat:@"%K contains[cd] %@",@"last name",searchText];
        searchResults = [self.neighbourData filteredArrayUsingPredicate:resultPredicate];
     }
// add predicates for other keys also if you want

        [tableView reloadData];
    }

建议:

• 避免键的单词之间有空格(不推荐 'first name'，推荐 'firstName')

• 并以全部小写形式保存值('Panda'、'Zoo' 最好保存为 'panda'、'zoo' 这将使搜索更简单)

关于ios - UISearchBar 在输入文本时不显示任何结果，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/41113536/