我试图在我的应用程序中显示通话记录详细信息，但 CallLog.Calls.CACHED_NAME 始终为某些联系人返回 null，即使它是已保存的姓名联系人。内置通话记录正确显示了这些联系人的姓名。

这是我的代码:

protected customAdapRecent doInBackground(Void... params) {

        ContentResolver resolver = context.getContentResolver();
        final String[] PROJECTION = new String[] {
                                               //     CallLog.Calls.CACHED_LOOKUP_URI,
                                                    CallLog.Calls.NUMBER,
                                                    CallLog.Calls.CACHED_NAME,
                                                    CallLog.Calls.TYPE,
                                                    CallLog.Calls.DATE,
                                                    CallLog.Calls.DURATION
                                                };

        Cursor cursor = resolver.query(CallLog.Calls.CONTENT_URI, PROJECTION, null, null, CallLog.Calls.DATE + " DESC");
        if(cursor.getCount() > 0)
        {
            int iNumber = cursor.getColumnIndex(CallLog.Calls.NUMBER);
            int iName = cursor.getColumnIndex(CallLog.Calls.CACHED_NAME);
            int iType = cursor.getColumnIndex(CallLog.Calls.TYPE);
            int iDate = cursor.getColumnIndex(CallLog.Calls.DATE);
            int iDuration = cursor.getColumnIndex(CallLog.Calls.DURATION);

            DateFormat datePattern = DateFormat.getDateInstance(DateFormat.FULL);

            String number;
            String name;
            String type;
            String date;
            String duration;
            String contactId;
            String callIs = "None";
            String prevDate = "";
            int callType;


            while (cursor.moveToNext())
            {

                if(cursor.getString(iName) == null)
                    Log.e("DEBUG: ", "Position: " + cursor.getPosition());

                number = cursor.getString(iNumber);
                name = cursor.getString(iName);
                type = cursor.getString(iType);
                String tempdate = cursor.getString(iDate);
                Long tempDate = Long.parseLong(tempdate);
                date = datePattern.format(tempDate);

                if(prevDate.equalsIgnoreCase(date))
                {
                    prevDate = date;
                    date = "";
                }
                else
                    prevDate = date;
                //date = new Date(Long.valueOf(strdate));
                duration = cursor.getString(iDuration);
                callType = Integer.parseInt(type);
                switch (callType)
                {
                    case CallLog.Calls.OUTGOING_TYPE:
                        callIs = "OUT";
                        recentRow newRowO = new recentRow(number, name, date, duration, callIs);
                        listItem_recentOut.add(newRowO);
                        break;

                    case CallLog.Calls.INCOMING_TYPE:
                        callIs = "IN";
                        recentRow newRowI = new recentRow(number, name, date, duration, callIs);
                        listItem_recentIn.add(newRowI);
                        break;

                    case CallLog.Calls.MISSED_TYPE:
                        callIs = "MISS";
                        recentRow newRowM = new recentRow(number, name, date, duration, callIs);
                        listItem_recentMiss.add(newRowM);
                        break;

                }

                recentRow newRow = new recentRow(number, name, date, duration, callIs);
                //recentRow newRow = new recentRow(number, name, callIs);
                listItem_recentAll.add(newRow);
            }
            cursor.close();
            cAdapRecent = new customAdapRecent(context, listItem_recentAll);
        }

        return cAdapRecent;
    }

Log.e() 中给出的 Debug 语句也在打印。

我在查找中做错了什么吗？请。建议一种方法，因为我真的因此而受阻!

提前致谢...

最佳答案

我也遇到了这种奇怪的行为，并发现有时您无法立即获取联系人的姓名，即使您可以从 CallLog.Calls 中获取其他所有信息。我注意到，在该调用后大约一小时左右，您可以获取名称以及所有其他 CallLog.Calls 数据。很奇怪。如果您需要在通话后立即刷新，您可以像这样从 ContactsContract 中获取号码的名称:

 fun getNameForNumber(context: Context, number: String): String? {

        var res: String? = null
        try {
            val resolver = context.contentResolver
            val uri = Uri.withAppendedPath(ContactsContract.PhoneLookup.CONTENT_FILTER_URI, Uri.encode(number))
            val c = resolver.query(uri, arrayOf(ContactsContract.PhoneLookup.DISPLAY_NAME), null, null, null)

            if (c != null) {
                if (c.moveToFirst()) {
                    res = c.getString(c.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME))
                }
                c.close()
            }
        } catch (e: Exception) {
            e.printStackTrace()
        }

        return res
    }

奇怪的是，在您从 ContactsContract 中获取一个名称后，通过 CallLog.Calls.CACHED_NAME 以您执行此操作的方式获取名称后，运行异常。

这也是对@PeterB 和@shyam002 的回答

关于java - CallLog.Calls.CACHED_NAME 总是为一些已保存的联系人返回 null，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/46118210/