我有这个 XML 文档，它是 SOAP 请求的主体:

<?xml version="1.0" encoding="UTF-8"?>
<mes:SubmitStructureRequest xmlns:mes="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/message" xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:com="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/common" xmlns:str="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/structure" xmlns:reg="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/registry" xmlns:web="http://www.sdmx.org/resources/sdmxml/schemas/v2_1/webservices">
            <mes:Header>
               <mes:ID>TEST_DFD</mes:ID>
               <mes:Test>true</mes:Test>
               <mes:Prepared>2013-10-10</mes:Prepared>
               <mes:Sender id="TESTER"/>
               <mes:Receiver id="ESTAT"/>
            </mes:Header>
            <mes:SubmitStructureRequest action="Append">
               <str:Structures>
                  <str:Dataflows>
                     <str:Dataflow agencyID="ESTAT" id="DFD_TEST_21" version="1.0">
                        <com:Name xml:lang="en">Production in construction, total, building construction, civil engineering (Monthly)</com:Name>
                        <str:Structure>
                           <Ref agencyID="ESTAT" class="DataStructure" id="STS" package="datastructure" version="2.0"/>
                        </str:Structure>
                     </str:Dataflow>
                  </str:Dataflows>
               </str:Structures>
            </mes:SubmitStructureRequest>
</mes:SubmitStructureRequest>

我正在尝试使用这段 Java 代码解析它(流是前面提到的 xml):

InputStream stream = sourceData.getInputStream();
        try {
            XMLInputFactory factory = XMLInputFactory.newInstance();
            XMLStreamReader parser = factory.createXMLStreamReader(stream);
            while (parser.hasNext()) {
                int event = parser.next();
                if (event == XMLStreamConstants.START_ELEMENT) {
                    for(int i = 0 ; i < parser.getNamespaceCount(); i ++) {
                        String ns = parser.getNamespaceURI(i);
                        if(SdmxConstants.getNamespacesV1().contains(ns)) {
                            return SDMX_SCHEMA.VERSION_ONE;
                        }
                        if(SdmxConstants.getNamespacesV2().contains(ns)) {
                            return SDMX_SCHEMA.VERSION_TWO;
                        }
                        if(SdmxConstants.getNamespacesV2_1().contains(ns)) {
                            return SDMX_SCHEMA.VERSION_TWO_POINT_ONE;
                        }
                    }
                    throw new SdmxSyntaxException("Can not get Scheme Version from SDMX message.  Unable to determine structure type from Namespaces- please ensure this is a valid SDMX document");
                }
            }
            throw new SdmxSyntaxException(ExceptionCode.XML_PARSE_EXCEPTION, "No root node found");
        } catch(XMLStreamException e) {
            throw new SdmxSyntaxException(ExceptionCode.XML_PARSE_EXCEPTION, e);
        } finally {
            if(stream != null) {
                try {
                    stream.close();
                } catch (IOException e) {
                    throw new RuntimeException(e);
                }
            }
        }

在 int event = parser.next(); 我得到:

com.ctc.wstx.exc.WstxEOFException: Unexpected EOF in prolog

知道为什么会这样吗？

最佳答案

证据表明您实际上已尝试解析一个空流。

它说在尝试解析序言时发现了 EOF。您向我们展示的 XML 中的序言没有任何问题，特别是没有合理的理由让解析器遇到 EOF。因此，我推断您向我们展示的 XML 并不是解析器实际看到的内容。

关于java - 解析 XML 时序言中出现意外的 EOF，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40108159/