我在编写一个应用程序时遇到问题，该应用程序通过 SSH 从其他机器下载和上传文件。我遇到的问题是我可以很好地获取(下载)文件，但是当我尝试将它们放入(上传)到另一台服务器时，我得到一个 EOFError() 异常。当我查看 paramiko\sftp.py 中的 _write_all() 时，似乎错误是在它无法将任何数据写入流时引起的？我没有网络编程经验，所以如果有人知道它正在尝试做什么并且可以与我交流，我将不胜感激。

我编写了一个简化版本的函数，将我的连接处理为 ssh()。 runCommand() 显示了上传在我的应用程序中是如何失败的，而 simpleTest() 显示了 sftp put 如何工作，但除了我的 SFTP 对象的存储方式之外，我看不出 runCommand() 和 simpleTest() 之间有任何区别。一个存储在字典中，另一个单独存储。似乎如果字典是下载文件不起作用的问题，但事实并非如此。

有谁知道是什么导致了这种行为，或者可以推荐另一种方法来管理我的连接(如果这种方式导致问题)？

我正在使用 Python 2.7 和 Paramiko 1.7.6。我已经在 Linux 和 Windows 上测试了这段代码并得到了相同的结果。

编辑:现在包含代码。

import os
import paramiko

class ManageSSH:
     """Manages ssh connections."""
    def __init__(self):
        self.hosts = {"testbox": ['testbox', 'test', 'test']}
        self.sshConnections = {}
        self.sftpConnections = {}
        self.localfile = "C:\\testfile"
        self.remotefile = "/tmp/tempfile"
        self.fetchedfile = "C:\\tempdl"

    def ssh(self):
        """Manages ssh connections."""
        for host in self.hosts.keys():
            try:
                self.sshConnections[host]
                print "ssh connection is already open for %s" % host
            except KeyError, e:         # if no ssh connection for the host exists then open one
                # open ssh connection
                ssh = paramiko.SSHClient()
                ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
                ssh.connect(self.hosts[host][0], 22, self.hosts[host][1], self.hosts[host][2])
                self.sshConnections[host] = ssh
                print "ssh connection to %s opened" % host
            try:
                self.sftpConnections[host]
                print "sftp connection is already open for %s" % host
            except KeyError, e:
                # open sftp connection
                ssh = paramiko.SSHClient()
                ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
                ssh.connect(self.hosts[host][0], 22, self.hosts[host][1], self.hosts[host][2])
                self.sftpConnections[host] = ssh.open_sftp()
                print "sftp connection to %s opened" % host

    def runCommand(self):
        """run commands and return output"""
        for host in self.hosts:
            command = "if [ -d /tmp ]; then echo -n 1; else echo -n 0; fi"
            stdin, stdout, stderr = self.sshConnections[host].exec_command(command)
            print "%s executed on %s" % (command, host)
            print "returned %s" % stdout.read()
            self.sftpConnections.get(self.remotefile, self.fetchedfile)
            print "downloaded %s from %s" % (self.remotefile, host)
            self.sftpConnections[host].put(self.localfile, self.remotefile)
            print "uploaded %s to %s" % (self.localfile, host)
            self.sftpConnections[host].close()
            self.sshConnections[host].close()

    def simpleTest(self):
        host = "testbox"
        ssh = paramiko.SSHClient()
        ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
        ssh.connect(host, 22, 'test', 'test')
        sftp = ssh.open_sftp()
        print "sftp connection to %s opened" % host
        sftp.get(self.remotefile, self.fetchedfile)
        print "downloaded %s from %s" % (self.localfile, host)
        sftp.put(self.localfile, self.remotefile)
        print "uploaded %s to %s" % (self.localfile, host)
        sftp.close()

if __name__ == "__main__":
    test = ManageSSH()
    print "running test that works"
    test.simpleTest()
    print "running test that fails"
    test.ssh()
    test.runCommand()

输出:

running test that works
sftp connection to testbox opened
downloaded C:\testfile from testbox
uploaded C:\testfile to testbox
running test that fails
ssh connection to testbox opened
sftp connection to testbox opened
if [ -d /tmp ]; then echo -n 1; else echo -n 0; fi executed on testbox
returned 1
downloaded /tmp/tempfile from testbox
Traceback (most recent call last):
  File "paramikotest.py", line 71, in <module>
    test.runCommand()
  File "paramikotest.py", line 47, in runCommand
    self.sftpConnections[host].put(self.localfile, self.remotefile)
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 561, in put

    fr = self.file(remotepath, 'wb')
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 245, in open
    t, msg = self._request(CMD_OPEN, filename, imode, attrblock)
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 627, in _request
    num = self._async_request(type(None), t, *arg)
  File "C:\Python27\lib\site-packages\paramiko\sftp_client.py", line 649, in _async_request
    self._send_packet(t, str(msg))
  File "C:\Python27\lib\site-packages\paramiko\sftp.py", line 172, in _send_packet
    self._write_all(out)
  File "C:\Python27\lib\site-packages\paramiko\sftp.py", line 138, in _write_all

    raise EOFError()
EOFError

最佳答案

我能够解决我的问题。我应该使用 Paramiko.Transport，然后使用 paramiko.SFTPClient.from_transport(t) 创建 SFTPClient 而不是使用 open_sftp()来自 SSHClient()。

以下代码有效:

t = paramiko.Transport((host, 22))  
t.connect(username=username, password=password)  
sftp = paramiko.SFTPClient.from_transport(t)

关于python - 当 SFTP 对象存储在字典中时，为什么 Paramiko 会引发 EOFError()？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/5342350/