原始JSON数据(平面表格):
[
{"id":"1","first_name":"Jason","last_name":"Martin","start_date":"1996-07-25","end_date":"2006-07-25","salary":"1234.56","city":"Toronto","description":"Programmer","department":"Finance","active":"1"},
{"id":"2","first_name":"Alison","last_name":"Mathews","start_date":"1976-03-21","end_date":"1986-02-21","salary":"6661.78","city":"Vancouver","description":"Tester","department":"Finance","active":"1"},
{"id":"3","first_name":"James","last_name":"Smith","start_date":"1978-12-12","end_date":"1990-03-15","salary":"6544.78","city":"Vancouver","description":"Tester","department":"QA","active":"1"},
{"id":"4","first_name":"Celia","last_name":"Rice","start_date":"1982-10-24","end_date":"1999-04-21","salary":"2344.78","city":"Vancouver","description":"Manager","department":"HR","active":"1"},
{"id":"5","first_name":"Robert","last_name":"Black","start_date":"1984-01-15","end_date":"1998-08-08","salary":"2334.78","city":"Vancouver","description":"Tester","department":"IT","active":"1"},
{"id":"6","first_name":"Linda","last_name":"Green","start_date":"1987-07-30","end_date":"1996-01-04","salary":"4322.78","city":"New York","description":"Tester","department":"QA","active":"1"},
{"id":"7","first_name":"David","last_name":"Larry","start_date":"1990-12-31","end_date":"1998-02-12","salary":"7897.78","city":"New York","description":"Manager","department":"HR","active":"1"}
]
我需要这样调用函数:
nest(data,["city","description","department"])
第一个参数是整个数据集，第二个参数是定义嵌套级别的列数组。
预期的 JSON 输出:
[
{key: "city", value: "Toronto", count: 1, children:
[
{key: "description", value: "Programmer", count: 1, children:
[
{key: "department", value: "Finance", count: 1}
]
}
]
},
{key: "city", value: "Vancouver", count: 2, children:
[
{key: "description", value: "Tester", count: 3, children:
[
{key: "department", value: "Finance", count: 1},
{key: "department", value: "QA", count: 1},
{key: "department", value: "IT", count: 1}
]
},
{key: "description", value: "Manager", count: 1}
]
},
{key: "city", value: "New York", count: 2, children:
[
{key: "description", value: "Tester", count: 1, children:
[
{key: "department", value: "QA", count: 1}
]
},
{key: "description", value: "Manager", count: 1, children:
[
{key: "department", value: "HR", count: 1}
]
}
]
}
]
我已经尝试编写一些递归函数，但当我必须动态搜索树以避免重复时，我总是卡住。
最佳答案
认为这是一个有趣的小问题，所以我做了...但是，我同意那些问“到目前为止你尝试了什么”的人。通常，您应该讨论一个特定问题。
// Groups a flat array into a tree.
// "data" is the flat array.
// "keys" is an array of properties to group on.
function groupBy(data, keys) {
if (keys.length == 0) return data;
// The current key to perform the grouping on:
var key = keys[0];
// Loop through the data and construct buckets for
// all of the unique keys:
var groups = {};
for (var i = 0; i < data.length; i++)
{
var row = data[i];
var groupValue = row[key];
if (groups[groupValue] == undefined)
{
groups[groupValue] = new Array();
}
groups[groupValue].push(row);
}
// Remove the first element from the groups array:
keys.reverse();
keys.pop()
keys.reverse();
// If there are no more keys left, we're done:
if (keys.length == 0) return groups;
// Otherwise, handle further groupings:
for (var group in groups)
{
groups[group] = groupBy(groups[group], keys.slice());
}
return groups;
}
像这样调用方法:
var groupedData = groupBy(data, ["city","description","department"]);
此方法的数据输出如下所示:
{
"Toronto": {
"Programmer": {
"Finance": [
{
"id": "1", "first_name": "Jason", "last_name": "Martin", "start_date": "1996-07-25", "end_date": "2006-07-25", "salary": "1234.56", "city": "Toronto", "description": "Programmer", "department": "Finance", "active": "1"
}
]
}
},
"Vancouver": {
"Tester": {
"Finance": [
{
"id": "2", "first_name": "Alison", "last_name": "Mathews", "start_date": "1976-03-21", "end_date": "1986-02-21", "salary": "6661.78", "city": "Vancouver", "description": "Tester", "department": "Finance", "active": "1"
}
],
"QA": [
{
"id": "3", "first_name": "James", "last_name": "Smith", "start_date": "1978-12-12", "end_date": "1990-03-15", "salary": "6544.78", "city": "Vancouver", "description": "Tester", "department": "QA", "active": "1"
}
],
"IT": [
{
"id": "5", "first_name": "Robert", "last_name": "Black", "start_date": "1984-01-15", "end_date": "1998-08-08", "salary": "2334.78", "city": "Vancouver", "description": "Tester", "department": "IT", "active": "1"
}
]
},
"Manager": {
"HR": [
{
"id": "4", "first_name": "Celia", "last_name": "Rice", "start_date": "1982-10-24", "end_date": "1999-04-21", "salary": "2344.78", "city": "Vancouver", "description": "Manager", "department": "HR", "active": "1"
}
]
}
},
"New York": {
"Tester": {
"QA": [
{
"id": "6", "first_name": "Linda", "last_name": "Green", "start_date": "1987-07-30", "end_date": "1996-01-04", "salary": "4322.78", "city": "New York", "description": "Tester", "department": "QA", "active": "1"
}
]
},
"Manager": {
"HR": [
{
"id": "7", "first_name": "David", "last_name": "Larry", "start_date": "1990-12-31", "end_date": "1998-02-12", "salary": "7897.78", "city": "New York", "description": "Manager", "department": "HR", "active": "1"
}
]
}
}
}
因为组都是 javascript 对象，所以您不需要那个“计数”成员。您可以简单地使用数组的 .length 属性。
使用 javascript 的 for (var group in groups) 语法遍历组。
关于javascript - 将平面对象数组转换为嵌套对象数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/8318150/
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