我想编写一个测试，检查我的函数是否使用await关键字调用其他函数。

我希望我的测试失败:

async methodA() {
   this.methodB();
   return true; 
},

async methodA() {
   await this.methodB();
   return true;
},

methodA() {
   return this.methodB()
       .then(() => true);
},

const { stub } = require('sinon');
const { expect } = require('chai');

const testObject = {
    async methodA() {
        await this.methodB();
    },
    async methodB() {
        // some async code
    },
};

describe('methodA', () => {
    let asyncCheckMethodB;

    beforeEach(() => {
        asyncCheckMethodB = stub();
        stub(testObject, 'methodB').returns(new Promise(resolve => process.nextTick(resolve)).then(asyncCheckMethodB));
    });

    afterEach(() => {
        testObject.methodB.restore();
    });

    it('should await methodB', async () => {
        await testObject.methodA();
        expect(asyncCheckMethodB.callCount).to.be.equal(1);
    });
});

最佳答案

TLDR

如果methodA调用await上的methodB，则Promise返回的methodA将无法解析，直到Promise返回的methodB解析为止。

另一方面，如果methodA未在await上调用methodB，则Promise返回的methodA将立即解析Promise返回的methodB是否已解决。

因此，测试methodA是否在await上调用methodB仅仅是测试Promise返回的methodA是否等待Promise返回的methodB解析之后再解决:

const { stub } = require('sinon');
const { expect } = require('chai');

const testObject = {
  async methodA() {
    await this.methodB();
  },
  async methodB() { }
};

describe('methodA', () => {
  const order = [];
  let promiseB;
  let savedResolve;

  beforeEach(() => {
    promiseB = new Promise(resolve => {
      savedResolve = resolve;  // save resolve so we can call it later
    }).then(() => { order.push('B') })
    stub(testObject, 'methodB').returns(promiseB);
  });

  afterEach(() => {
    testObject.methodB.restore();
  });

  it('should await methodB', async () => {
    const promiseA = testObject.methodA().then(() => order.push('A'));
    savedResolve();  // now resolve promiseB
    await Promise.all([promiseA, promiseB]);  // wait for the callbacks in PromiseJobs to complete
    expect(order).to.eql(['B', 'A']);  // SUCCESS: 'B' is first ONLY if promiseA waits for promiseB
  });
});

describe('methodA', () => {

  beforeEach(() => {
    // stub methodB to return a Promise that never resolves
    stub(testObject, 'methodB').returns(new Promise(() => {}));
  });

  afterEach(() => {
    testObject.methodB.restore();
  });

  it('should NOT await methodB', async () => {
    // passes if promiseA did NOT wait for promiseB
    // times out and fails if promiseA waits for promiseB
    await testObject.methodA();
  });

});

it('should result in [1, 2]', async () => {
  const order = [];
  const promise1 = Promise.resolve().then(() => order.push('1'));
  const promise2 = Promise.resolve().then(() => order.push('2'));
  expect(order).to.eql([]);  // SUCCESS: callbacks are still queued in PromiseJobs
  await Promise.all([promise1, promise2]);  // let the callbacks run
  expect(order).to.eql(['1', '2']);  // SUCCESS
});

it('should result in [2, 1]', async () => {
  const order = [];
  let savedResolve;
  const promise1 = new Promise((resolve) => {
    savedResolve = resolve;  // save resolve so we can call it later
  }).then(() => order.push('1'));
  const promise2 = Promise.resolve().then(() => order.push('2'));
  expect(order).to.eql([]);  // SUCCESS
  savedResolve();  // NOW resolve the first Promise
  await Promise.all([promise1, promise2]);  // let the callbacks run
  expect(order).to.eql(['2', '1']);  // SUCCESS
});

What is the smart way to test if await was used in the function call?

关于javascript - JavaScript/Mocha-如何测试是否已等待函数调用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/54998608/