我有两个 sql 插入操作(比如表 A 和 B 中的示例)，它们在一个事务中，因为我希望数据库保持一致，也就是说，A 中的元组必须在 B 中有引用。

在第二个插入中，我需要来自第一个的 ID，但在提交事务之前我没有得到这个 ID。
所以我卡住了。我不想从事务中取出第一个插入，可能会发生第一个插入正常但第二个不正常的情况，从而使我在数据库中处于不一致的状态。

这种情况下的最佳做法是什么？

编辑:这是代码:

TransactionStatus txStatus = transactionManager.getTransaction(txDefinition);
try{
    Integer aId = insertIntoA();
    insertIntoB(aId);
}catch(){
    transactionManager.rollback(txStatus);
    throw new CustomException(); 
}
transactionManager.commit(txStatus);

我想指出的是，在我提交事务之前我不会得到aId，因此将 null 插入 B。

最佳答案

在 MySQL 上，在 insertIntoA 中你应该能够做:

SELECT LAST_INSERT_ID()

...在您用于插入的同一连接上，假设它是您要查找的 identity 列值。

编辑:如果您这样做但没有效果(根据您的评论)，我会查看中间层以了解发生了什么。 MySQL 没问题:

mysql> create table A (id int(11) not null auto_increment, descr varchar(64), primary key (id));
Query OK, 0 rows affected (0.13 sec)

mysql> create table B (fk int(11) not null, descr varchar(64));
Query OK, 0 rows affected (0.06 sec)

mysql> start transaction;
Query OK, 0 rows affected (0.00 sec)

mysql> insert into A (descr) values ('Testing 1 2 3');
Query OK, 1 row affected (0.00 sec)

mysql> select last_insert_id();
+------------------+
| last_insert_id() |
+------------------+
|                1 |
+------------------+
1 row in set (0.03 sec)

mysql> insert into B (fk, descr) values (1, 'Test complete');
Query OK, 1 row affected (0.00 sec)

mysql> commit;
Query OK, 0 rows affected (0.03 sec)

mysql> select * from A;
+----+---------------+
| id | descr         |
+----+---------------+
|  1 | Testing 1 2 3 |
+----+---------------+
1 row in set (0.02 sec)

mysql> select * from B;
+----+---------------+
| fk | descr         |
+----+---------------+
|  1 | Test complete |
+----+---------------+
1 row in set (0.00 sec)

mysql> start transaction;
Query OK, 0 rows affected (0.00 sec)

mysql> insert into A (descr) values ('Second test');
Query OK, 1 row affected (0.01 sec)

mysql> select last_insert_id();
+------------------+
| last_insert_id() |
+------------------+
|                2 |
+------------------+
1 row in set (0.00 sec)

mysql> insert into B (fk, descr) values (2, 'Second test complete');
Query OK, 1 row affected (0.00 sec)

mysql> commit;
Query OK, 0 rows affected (0.08 sec)

mysql> select * from A;
+----+---------------+
| id | descr         |
+----+---------------+
|  1 | Testing 1 2 3 |
|  2 | Second test   |
+----+---------------+
2 rows in set (0.02 sec)

mysql> select * from B;
+----+----------------------+
| fk | descr                |
+----+----------------------+
|  1 | Test complete        |
|  2 | Second test complete |
+----+----------------------+
2 rows in set (0.00 sec)

mysql> start transaction;
Query OK, 0 rows affected (0.00 sec)

mysql> insert into A (descr) values ('We''ll roll this one back.');
Query OK, 1 row affected (0.00 sec)

mysql> select last_insert_id();
+------------------+
| last_insert_id() |
+------------------+
|                3 |
+------------------+
1 row in set (0.00 sec)

mysql> insert into B (fk, descr) values (3, 'Won''t see this one.');
Query OK, 1 row affected (0.00 sec)

mysql> select * from B;
+----+----------------------+
| fk | descr                |
+----+----------------------+
|  1 | Test complete        |
|  2 | Second test complete |
|  3 | Won't see this one.  |
+----+----------------------+
3 rows in set (0.00 sec)

mysql> rollback;
Query OK, 0 rows affected (0.03 sec)

mysql> select * from A;
+----+---------------+
| id | descr         |
+----+---------------+
|  1 | Testing 1 2 3 |
|  2 | Second test   |
+----+---------------+
2 rows in set (0.00 sec)

mysql> select * from B;
+----+----------------------+
| fk | descr                |
+----+----------------------+
|  1 | Test complete        |
|  2 | Second test complete |
+----+----------------------+
2 rows in set (0.00 sec)

关于java - 有两个sql插入的事务，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/1543756/