给定以下表结构，我想返回一个 Eloquent 集合或至少将原始数据库结果转换为关联数组以便于迭代。

建筑物

+----+---------------+
| id | building_name |
+----+---------------+
|  1 | Building 1    |
|  2 | Building 2    |
+----+---------------+

房间

+----+-----------+-------------+
| id | room_name | building_id |
+----+-----------+-------------+
|  1 | Room 1    |           1 |
|  2 | Room 2    |           1 |
|  3 | Room 3    |           2 |
+----+-----------+-------------+

维护日志

+----+-------------------+---------+---------------------+
| id | maintenance_value | room_id |      created_at     |
+----+-------------------+---------+---------------------+
|  1 | Cleaned           |       1 | 2015-09-10 00:54:59 |
|  2 | Cleaned           |       1 | 2015-09-13 01:55:59 |
|  3 | Cleaned           |       2 | 2015-09-09 02:56:59 |
|  4 | Cleaned           |       2 | 2015-09-14 03:57:59 |
|  5 | Cleaned           |       3 | 2015-09-08 04:58:59 |
|  6 | Cleaned           |       3 | 2015-09-15 05:59:59 |
+----+-------------------+---------+---------------------+

现在使用以下原始数据库查询..

$results = DB::select('
  select b.building_name,r.room_name,x.maxdate FROM buildings b
  join rooms r on r.building_id = b.id
  join (select room_id,max(created_at) as maxdate from maintenancelog group by room_id) x on x.room_id=room.id
  having x.maxdate < DATE_SUB(NOW(), INTERVAL 10 DAY)');

返回

Array
(
    [0] => stdClass Object
        (
            [building_name] => Building 1
            [room_name] => Room 1
            [maxdate] => 2015-09-13 01:55:59
        )

    [1] => stdClass Object
        (
            [building_name] => Building 1
            [room_name] => Room 2
            [maxdate] => 2015-09-14 03:57:59 
        )

    [2] => stdClass Object
        (
            [building_name] => Building 2
            [room_name] => Room 3
            [maxdate] => 2015-09-15 05:59:59
        )

是否有 Laravel 辅助函数可以给定一个数组，我可以指定键和分组顺序？有点像，按 building_name、room_name 分组，这样它将返回一个集合或关联数组，其中以“buildings”和“rooms”作为键以使迭代更容易？我可以 build 一个，但这似乎是一项常见的任务。 (我搜索过)

我正在使用 Eloquent 并为表格制作了模型，但查询太复杂了，我无法弄清楚如何将其转换为 Eloquent 语句。那么即使有一种方法可以使用现有模型创建集合？

(请注意，我已经弄清楚如何使用关系和查询范围从维护日志 -> 房间 -> 建筑物向后工作。但它将建筑物置于关系的最低级别，我希望它是第一个)

最佳答案

在建筑类中:

public function rooms(){
    return $this->hasMany('App\Room');
}

在房间类中:

public function maintenanceLog(){
    return $this->hasMany('App\MaintenanceLog');
}

在 MaintenanceLog 类中:

public function scopeLongest($query){ //you can name it as you like ofc.
    return $query->orderBy('created_at','desc')->first();
}

最后你可以使用:

foreach(Building::all() as $building){
    foreach($building->rooms() as $room){
        echo 'building: ' . $building->building_name . ' room: ' . $room->room_name . ' maxdate: ' . $room->maintenanceLog()->longest()->created_at;
    }
}

关于php - Laravel 5.1 从原始数据库(或只是一个数组)创建集合或关联数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32792855/