class ViewController: UIViewController {

    @IBOutlet weak var inputField: UITextField!
    @IBOutlet weak var output: UITextView!

    var guesses : UInt = 0
    var number : UInt32 = 0
    var gameOver = false
    let MAX_GUESSES : UInt = 8

    @IBAction func guess(sender: UIButton) {
        var possibleGuess : Int? = inputField.text.toInt()

        if let guess = possibleGuess {
            // possibleGuess exists!
        } else {
            consoleOut("Please input a valid number!\n")
            clearInput()
        }

        if UInt32(guess) > Int(number) {
            consoleOut("\(guess): You guessed too high!\n")
            ++guesses
        } else if UInt32(guess) < number {
            consoleOut("\(guess): You guessed too low!\n")
            ++guesses
        } else {
            consoleOut("\n\(guess): You win!\n")
            consoleOut("Go again? (Y)")
            guesses = 0
            gameOver = true
        }
        clearInput()

        if (guesses == MAX_GUESSES) {
            consoleOut("\nYou lose :(\n")
            consoleOut("Go again? (Y)")
            guesses = 0
            gameOver = true
        }

    }

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.

        number = generateNewNumber()
        consoleOut("Gondolkodom egy számot...\n")
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    func consoleOut(text : String) {
        output.text = output.text + text
    }


    func generateNewNumber () -> UInt32 {
        return arc4random_uniform(100)
    }

    func clearInput() {
        inputField.text = ""
    }

}

这是我使用的代码，我在 if UInt32(guess) > Int(number) { 处收到错误消息。我真的受不了了。

(swift) Error: can not invoke '>' with an argument list of type '(UInt32, @lvalue UInt32)'

最佳答案

* 这不完全是你的问题，但它可能会告诉你一个解决它的方法:) *

这一定是一个 Swift 错误，就像 ObjectiveC 的许多其他错误一样。 我在尝试比较 arc4random() 数字(它是 UInt32 类型)与 UInt32() 转换字符串时遇到了同样的问题，我得到了同样的错误，这在我的例子中更离谱，因为这两个数字是同一类型。这让我认为类型转换一定没有产生预期的结果。

我虽然创建了一个辅助 UIint32 变量并为其赋值 UInt32(theString)，但是 Swift 不允许您在定义变量时将 String 转换为 UInt32，因此我不得不创建一个辅助变量以转换为 Int，并且然后将 Int 转换为 UInt32 以便能够比较两个数字:

var theString = "5"
var randomNumber = arc4random() % 10

var UInt32Number = UInt32(theString)
   // => ERROR: "Cannot invoke 'init' with an argument of type '@lvalue String!'
   // (this is where I realized the comparison line could be suffering from the same problem)
if randomNumber == UInt32(theString) { ... }
  // No error here 'cos Swift is supposed to have casted theString into a UInt32
  // ...but surprisingly it prompts an ERROR saying it can't compare a UInt32 with a UInt32 (WTF!)
  // And here's where I go crazy, because watch what happens in the next lines:

var intValue = theString.toInt()
var UInt32Value = UInt32(intValue!) 
if randomNumber == UInt32Value { ... } // => NOW IT WORKS!!

结论:Swift 没有在比较中创建转换类型，即使它应该这样做。有时它看起来很糟糕。使用具有集合类型的辅助变量可以解决这个问题。

关于swift - ( swift )错误 : can not invoke '>' with an argument list of type '(UInt32, @lvalue UInt32)' ，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/25898004/