我正在使用 PHP 中的 glob 函数来浏览目录并尝试仅匹配图像文件。这是可行的，但是当我尝试计算每个目录中的图像时，它会为其他目录重复第一个目录的计数。例如，目录 1 有 6 张图像，目录 2 有 4 张图像，但是当我尝试显示每个目录的计数时，它显示目录 2 的 6 张图像，依此类推。

这是我的代码:

public function viewphotoalbumsAction()
{
    $identity = $this->identity();
    $dirname = array();
    $files = array();

    foreach (glob(getcwd() . '/public/images/profile/' . $identity . '/albums/*', GLOB_ONLYDIR) as $dir) {
        $dirname[] = basename($dir);

        foreach (glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE) as $images) {
            $files[] = $images;
        }
    }
    //var_dump($files); exit;

    $data = array(
        'albums' => array_values($dirname),
        'files'  => $files,
    );

    return new ViewModel(array('album' => $data['albums'], 'files' => $data['files']));
}

var_dump()的结果

 array(9) { [0]=> string(96) "C:\xampp\htdocs/public/images/profile/fooboy/albums/bone mom's album_2017-07-03/massive snow.jpg"
[1]=> string(91) "C:\xampp\htdocs/public/images/profile/fooboy/albums/bone mom's album_2017-07-03/mom-jon.jpg" 
[2]=> string(90) "C:\xampp\htdocs/public/images/profile/fooboy/albums/bone mom's album_2017-07-03/sunset.jpg" 
[3]=> string(85) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/cref.jpg" 
[4]=> string(88) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/diploma.jpg" 
[5]=> string(86) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/eeyor.jpg" 
[6]=> string(93) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/frother-jaws.jpg" 
[7]=> string(88) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/frother.jpg" 
[8]=> string(93) "C:\xampp\htdocs/public/images/profile/fooboy/albums/random photos_2017-07-02/goat_singing.jpg" }

它正在按预期从每个目录获取所有图像，但我真正需要做的是将图像分开，这样我就可以对每个目录进行准确计数，而不仅仅是让它显示整个计数 (9)

查看代码:

<div class="w3-col m7">
    <div class="w3-row-padding">
        <div class="w3-col m12">
            <div class="w3-card-2 w3-round w3-white">
                <div class="w3-container w3-padding" id="view-photo-albums">
                    <p class="w3-center">Current Albums</p>
                    <br>
                    <?php
foreach ($this->album as $albums):
    ?>
                    <p>
                        <?php echo $albums; ?> - Number of images: <?php echo $this->files; ?>
                    </p>
                    <?php endforeach; ?>
                </div>
            </div>
        </div>
    </div>
</div>

如有任何帮助，我们将不胜感激。

更新:
我不能像对$data['albums']那样对$data['files']使用array_values给出数组到字符串转换的警告。

最佳答案

这段代码有问题:

foreach (glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE) as $images) {
     $files[] = $images;
}

变量 $dir 用于迭代第一次调用 glob() 返回的数组:

foreach (glob(...) as $dir) {
    ...
}

它在第一个 foreach 循环结束后的值是在 foreach 循环中分配给它的最后一个值。

最后，$data['albums'] 包含所有目录名称，$data['files'] 包含最后一个目录中的文件名称$data['albums'] 中列出的目录。

I cannot use array_values for $data['files'] as I did for $data['albums'] as it is giving a warning of array to string conversion.

array_values()不会为 $dirname 和 $files 生成任何新内容。如果它们被创建(!)，这两个变量包含由以 0 开头的序列号索引的值；这正是 array_values() 返回的内容。

您发布的代码的意图对我来说不是很清楚。我假设您想显示相册列表以及每个相册包含多少张图像。

我会这样做:

public function viewphotoalbumsAction()
{
    $identity = $this->identity();

    // Always initialize the arrays before putting values into them.
    // Without this, if the first glob() returns an empty array, the outer
    // foreach loop never runs and both $dirname and $files end up being undefined
    // and this produces trouble in the code that uses these variables later.
    $dirname = array();
    // This will be a two dimensional array. It is indexed by directory
    // names and contains the lists of files for each directory.
    $files   = array();

    // The outer loop enumerates the albums
    foreach (glob(getcwd() . '/public/images/profile/' . $identity . '/albums/*', GLOB_ONLYDIR) as $dir) {
        // The directory name is the album name
        $albumName = basename($dir);

        // Put the album name in $dirname[]
        // This is not really needed as we also have the album name
        // as key in $files but can be useful if you want to keep more
        // information about each album
        $dirname[] = $albumName;

        // Initialize the list of images of this album
        $files[$albumName] = array();

        // The inner loop enumerates the images of this directory
        foreach (glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE) as $images) {
            $files[] = $images;
        }
    }

    // Prepare the data for display
    $data = array(
        'albums' => $dirname,
        'files'  => $files,
    );

    return new ViewModel($data);
}

View (忽略了 HTML 包装器，就这样没问题):

<?php foreach ($this->files as $albumName => $listFiles): ?>
    <p>
        <?php echo $albumName; ?> - Number of images: <?php echo count($listFiles); ?>
    </p>
<?php endforeach; ?>

需要注意的是，内部的 foreach 循环甚至都不需要，因为它所做的只是将 glob() 返回的数组中的值一个一个地复制到一个新数组。

将 glob() 返回的值存储到 $files[$albumName] 中会更快、更容易阅读和理解。由于存储在 $dirname 中的值从未被使用过，因此可以完全省略该变量并且函数变得更短(省略注释):

public function viewphotoalbumsAction()
{
    $identity = $this->identity();
    $files    = array();

    foreach (glob(getcwd().'/public/images/profile/'.$identity.'/albums/*', GLOB_ONLYDIR) as $dir) {
        $albumName = basename($dir);
        $files[$albumName] = glob($dir . '/*.{jpg,png,gif}', GLOB_BRACE);
    }

    return new ViewModel(array('files' => $files));
}

关于php - 对两个目录重复图像计数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/44893586/