我收到的警告是:

Warning: mysqli_result::fetch_array() expects parameter 1 to be long, object given in...line 103.

我在第 103 行旁边注释了 while ($row = $result->fetch_array($result)) {

问题 2:我可以将其中的任何内容存储在包含文件中吗？

问题 3:对于 $query，我可以将这些 Buyer、Seller 中的任何一个存储在某个数组中吗？怎么办？

/* FETCH CONTACT INFORMATION */

$query = ("SELECT * FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') AND leadstatus = 'New' ORDER BY date DESC");

$ID = $row ['ID'];     
$firstname = $row ['firstname'];     
$lastname = $row['lastname'];
$ID = $row['ID'];   
$partner  = $row['spousefirst'];   
$phonecell = $row['phonecell'];
$email = $row['email'];
$date = $row['date'];
$contacttype = $row['contacttype'];
$agentassigned = $row['agentassigned'];
$leadstatus = $row['leadstatus'];

$result = $mysqli->query($query) or die ("Error: ".mysqli_error($mysqli));

echo'
  <table class="results" id="results">
    <thead> 
      <tr> 
        <th width="10"><input type="checkbox" name="checkAll" id="checkAll" class="checkall" value="check all"></th>
        <th>NAME</td> 
        <th>PARTNER</td> 
        <th>PHONE</td> 
        <th>EMAIL</td> 
        <th>DATE</td> 
        <th>TYPE</td> 
        <th>AGENT</td> 
        <th>STATUS</td> 
        <th>NOTES</td> 
        <th>TASKS</td> 
        <th>&nbsp;</td>
       </tr> 
     </thead>';

while ($row = $result->fetch_array($result)) {  // THIS IS LINE 103

      echo'
     <tbody>       
       <tr>
        <td width="10"><input type="checkbox" name="" id="" value="'.$ID.'"></td>
        <td><a href="/backend/leads/view/?ID='.$ID.'"><strong>'.$firstname.' '.$lastname.'</strong></a></td>
        <td><a href="/backend/leads/view/?ID='. $ID.'">'.$partner.'</a></td>
        <td>'.$phonecell.'</td>
        <td><a href="mailto:'. $email.'">'.$email.'</a></td>
        <td>'.date("M jS, g:i A", strtotime($date)).'</td>
        <td>'.$contacttype.'</td>
        <td>'.$agentassigned.'</td>
        <td>'.$leadstatus.'</td>
        <td><a href="/backend/contacts/notes.php?ID='.$ID.'">View</a> +</td>
        <td><a href="/backend/contacts/todo.php?ID='.$ID.'">View</a> +</td>
        <td><a href="/backend/contacts/deletesuccess.php?ID='.$ID.'">D</a></td>
       </tr>
     </tbody>       
    </table>';

}
?>

最佳答案

在面向对象模式下，参数为fetch_array()指定获取类型 ( MYSQLI_ASSOC, MYSQLI_NUM )，并且不获取结果资源。

while ($row = $result->fetch_array(MYSQLI_ASSOC)) {

那么在你的循环中，我们假设你想使用来自 $row 的 key 而不是普通变量。从上方将变量赋值移动到循环中。

while ($row = $result->fetch_array(MYSQLI_ASSOC)) {

  // Move these assignments into the loop so they are available to your
  // echo statement when constructing your <tbody>
  $ID = $row ['ID'];     
  $firstname = $row ['firstname'];     
  $lastname = $row['lastname'];
  $partner  = $row['spousefirst'];   
  $phonecell = $row['phonecell'];
  $email = $row['email'];
  $date = $row['date'];
  $contacttype = $row['contacttype'];
  $agentassigned = $row['agentassigned'];
  $leadstatus = $row['leadstatus'];

  echo'
 <tbody>       
   <tr>
    <td width="10"><input type="checkbox" name="" id="" value="'.$ID.'"></td>
    <td><a href="/backend/leads/view/?ID='.$ID.'"><strong>'.$firstname.' '.$lastname.'</strong></a></td>
    <td><a href="/backend/leads/view/?ID='. $ID.'">'.$partner.'</a></td>
    <td>'.$phonecell.'</td>
    <td><a href="mailto:'. $email.'">'.$email.'</a></td>
    <td>'.date("M jS, g:i A", strtotime($date)).'</td>
    <td>'.$contacttype.'</td>
    <td>'.$agentassigned.'</td>
    <td>'.$leadstatus.'</td>
    <td><a href="/backend/contacts/notes.php?ID='.$ID.'">View</a> +</td>
    <td><a href="/backend/contacts/todo.php?ID='.$ID.'">View</a> +</td>
    <td><a href="/backend/contacts/deletesuccess.php?ID='.$ID.'">D</a></td>
   </tr>
 </tbody>       
</table>';

}

编辑

关于你的其他几个问题...

我会说将其存储在包含文件中并没有太多好处。它的代码不多，如果您不打算在其他地方重用它，那么将它移出此文件不会有任何好处。

您的查询是静态的，没有使用任何 PHP 变量。因此，将它们存储在数组中也没有太大好处，这将需要在 PHP 中进行额外的工作才能转换为 SQL。

$options = array('Buyer','Seller','Buyer / Seller','Investor');
// Join them into a string and quote both ends of it.
// If this includes any user input, you must call `$mysqli->real_escape_string()` on _each_ of them.
// Since in this one instance it is static in your code though without variables, that isn't necessary here
$options = "'" . implode("','", $options) . "'";
$query = ("SELECT * FROM contacts WHERE contacttype IN ($options) AND leadstatus = 'New' ORDER BY date DESC");

关于php - 故障排除 "Warning: mysqli_result::fetch_array() expects parameter 1 to be long, object given"，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/11269269/