我当时正在开发我的文字冒险游戏，想知道是否有更简单的方法来编写重复的代码块，例如我下面的代码块。

在此 block 中，向用户呈现 N、E、S、W 表示北、东、南和西。所以我分别编写每个监听器，并在每个监听器中包含一个 try/catch block 。但是整个代码块现在看起来确实是重复的。

这是代码块:

btnNorth.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            tvIntro.setText("You go north");
            String testString = "nothing";
            try {
                testString = Encounter.EncounterGeneratorText();
            } catch (Exception e) {
                    e.printStackTrace();
                }
            testString = Encounter.EncounterGeneratorText();
            tvIntro.setText(testString);
            try {
                Thread.sleep(500);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            tvIntro.setText(testString);            
        }
    });

    btnEast.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            tvIntro.setText("You go east");
            String testString = "nothing";
            try {
                testString = Encounter.EncounterGeneratorText();
            } catch (Exception e) {
                    e.printStackTrace();
                }
            testString = Encounter.EncounterGeneratorText();
            tvIntro.setText(testString);
            try {
                Thread.sleep(500);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            tvIntro.setText(testString);
        }
    });

    btnSouth.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            tvIntro.setText("You go south");
            String testString = "nothing";
            try {
                testString = Encounter.EncounterGeneratorText();
            } catch (Exception e) {
                    e.printStackTrace();
                }
            testString = Encounter.EncounterGeneratorText();
            tvIntro.setText(testString);
            try {
                Thread.sleep(500);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            tvIntro.setText(testString);
        }
    });

    btnWest.setOnClickListener(new OnClickListener() {
        @Override
        public void onClick(View v) {
            tvIntro.setText("you go west");
            String testString = "nothing";
            try {
                testString = Encounter.EncounterGeneratorText();
            } catch (Exception e) {
                    e.printStackTrace();
                }
            testString = Encounter.EncounterGeneratorText();
            tvIntro.setText(testString);
            try {
                Thread.sleep(500);
            } catch (InterruptedException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            tvIntro.setText(testString);
        };
    });

最佳答案

您可以创建一个所有按钮都将使用的 OnClickListener，在该 OnClickListener 中，您将检测哪个按钮被单击并在 switch 语句中执行特定于方向的任务。

像这样:

private OnClickListener DirectionClickListner = new OnClickListener() {
    public void onClick(View v) {
        switch (v.getId()) {
        case R.id.north:
            //Set your strings for North
            break;
        case R.id.west:
            //Set your strings for West
            break;
        case R.id.east:
            //Set your strings for East
            break;
        case R.id.south:
            //Set your strings for South
            break;
        }
    }
};

关于java - 我的代码是不是太重复了？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6961995/