从 C# 提交带有 multipart/form-data 内容类型的 HTTP POST 请求的最简单方法是什么？必须有比构建我自己的请求更好的方法。

我问的原因是使用此 api 将照片上传到 Flickr:

http://www.flickr.com/services/api/upload.api.html

最佳答案

如果您使用的是 .NET 4.5，请使用:

public string Upload(string url, NameValueCollection requestParameters, MemoryStream file)
        {

            var client = new HttpClient();
            var content = new MultipartFormDataContent();

            content.Add(new StreamContent(file));
            System.Collections.Generic.List<System.Collections.Generic.KeyValuePair<string, string>> b = new List<KeyValuePair<string, string>>();
            b.Add(requestParameters);
            var addMe = new FormUrlEncodedContent(b);

            content.Add(addMe);
            var result = client.PostAsync(url, content);
            return result.Result.ToString();
        }

否则根据 Ryan 的回答，我下载了库并稍微调整了一下。

  public class MimePart
        {
            NameValueCollection _headers = new NameValueCollection();
            byte[] _header;

            public NameValueCollection Headers
            {
                get { return _headers; }
            }

            public byte[] Header
            {
                get { return _header; }
            }

            public long GenerateHeaderFooterData(string boundary)
            {
                StringBuilder sb = new StringBuilder();

                sb.Append("--");
                sb.Append(boundary);
                sb.AppendLine();
                foreach (string key in _headers.AllKeys)
                {
                    sb.Append(key);
                    sb.Append(": ");
                    sb.AppendLine(_headers[key]);
                }
                sb.AppendLine();

                _header = Encoding.UTF8.GetBytes(sb.ToString());

                return _header.Length + Data.Length + 2;
            }

            public Stream Data { get; set; }
        }

        public string Upload(string url, NameValueCollection requestParameters, params MemoryStream[] files)
        {
            using (WebClient req = new WebClient())
            {
                List<MimePart> mimeParts = new List<MimePart>();

                try
                {
                    foreach (string key in requestParameters.AllKeys)
                    {
                        MimePart part = new MimePart();

                        part.Headers["Content-Disposition"] = "form-data; name=\"" + key + "\"";
                        part.Data = new MemoryStream(Encoding.UTF8.GetBytes(requestParameters[key]));

                        mimeParts.Add(part);
                    }

                    int nameIndex = 0;

                    foreach (MemoryStream file in files)
                    {
                        MimePart part = new MimePart();
                        string fieldName = "file" + nameIndex++;

                        part.Headers["Content-Disposition"] = "form-data; name=\"" + fieldName + "\"; filename=\"" + fieldName + "\"";
                        part.Headers["Content-Type"] = "application/octet-stream";

                        part.Data = file;

                        mimeParts.Add(part);
                    }

                    string boundary = "----------" + DateTime.Now.Ticks.ToString("x");
                    req.Headers.Add(HttpRequestHeader.ContentType, "multipart/form-data; boundary=" + boundary);

                    long contentLength = 0;

                    byte[] _footer = Encoding.UTF8.GetBytes("--" + boundary + "--\r\n");

                    foreach (MimePart part in mimeParts)
                    {
                        contentLength += part.GenerateHeaderFooterData(boundary);
                    }

                    //req.ContentLength = contentLength + _footer.Length;

                    byte[] buffer = new byte[8192];
                    byte[] afterFile = Encoding.UTF8.GetBytes("\r\n");
                    int read;

                    using (MemoryStream s = new MemoryStream())
                    {
                        foreach (MimePart part in mimeParts)
                        {
                            s.Write(part.Header, 0, part.Header.Length);

                            while ((read = part.Data.Read(buffer, 0, buffer.Length)) > 0)
                                s.Write(buffer, 0, read);

                            part.Data.Dispose();

                            s.Write(afterFile, 0, afterFile.Length);
                        }

                        s.Write(_footer, 0, _footer.Length);
                        byte[] responseBytes = req.UploadData(url, s.ToArray());
                        string responseString = Encoding.UTF8.GetString(responseBytes);
                        return responseString;
                    }
                }
                catch
                {
                    foreach (MimePart part in mimeParts)
                        if (part.Data != null)
                            part.Data.Dispose();

                    throw;
                }
            }
        }

关于c# - 如何从 C# 提交 multipart/form-data HTTP POST 请求，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/1203811/