我确信 MONGO_URI 是正确的，因为它在 pymongo 中运行良好。 但是当使用 flask_pymongo 时，它不起作用...... 这是我的测试代码:

from flask import Flask
from flask_pymongo import PyMongo
app = Flask(__name__)

app.config['MONGO_URI'] ='mongodb://root:aaa2016@localhost:27017/mongo_test'
mongo = PyMongo(app, config_prefix='MONGO')


@app.route('/')
def hello_world():
    mongo.db.user.insert({'username': "aaa"})
    return 'Hello World!'


if __name__ == '__main__':
    app.run()

运行并访问127.0.0.1:5000，返回500..

OperationFailure: Authentication failed.
127.0.0.1 - - [21/Jun/2016 20:40:25] "GET / HTTP/1.1" 500 -

我们将不胜感激。

更新: 这是回溯:

File "C:\Python27\lib\site-packages\flask\app.py", line 2000, in __call__
return self.wsgi_app(environ, start_response)
File "C:\Python27\lib\site-packages\flask\app.py", line 1991, in wsgi_app
response = self.make_response(self.handle_exception(e))
File "C:\Python27\lib\site-packages\flask\app.py", line 1567, in       handle_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1988, in wsgi_app
response = self.full_dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1641, in  full_dispatch_request
rv = self.handle_user_exception(e)
File "C:\Python27\lib\site-packages\flask\app.py", line 1544, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "C:\Python27\lib\site-packages\flask\app.py", line 1639, in full_dispatch_request
rv = self.dispatch_request()
File "C:\Python27\lib\site-packages\flask\app.py", line 1625, in dispatch_request
return self.view_functions[rule.endpoint](**req.view_args)
File "F:\PycharmProjects\flask_\flask_.py", line 12, in hello_world
mongo.db.user.insert({'username': "aaa"})
File "C:\Python27\lib\site-packages\pymongo\collection.py", line 2203, in insert
with self._socket_for_writes() as sock_info:
File "C:\Python27\lib\contextlib.py", line 17, in __enter__
return self.gen.next()
File "C:\Python27\lib\site-packages\pymongo\mongo_client.py", line 718, in _get_socket
with server.get_socket(self.__all_credentials) as sock_info:
File "C:\Python27\lib\contextlib.py", line 17, in __enter__
return self.gen.next()
File "C:\Python27\lib\site-packages\pymongo\server.py", line 152, in get_socket
with self.pool.get_socket(all_credentials, checkout) as sock_info:
File "C:\Python27\lib\contextlib.py", line 17, in __enter__
return self.gen.next()
File "C:\Python27\lib\site-packages\pymongo\pool.py", line 541, in get_socket
sock_info.check_auth(all_credentials)
File "C:\Python27\lib\site-packages\pymongo\pool.py", line 306, in  check_auth
auth.authenticate(credentials, self)
File "C:\Python27\lib\site-packages\pymongo\auth.py", line 436, in authenticate
auth_func(credentials, sock_info)
File "C:\Python27\lib\site-packages\pymongo\auth.py", line 416, in _authenticate_default
return _authenticate_scram_sha1(credentials, sock_info)
File "C:\Python27\lib\site-packages\pymongo\auth.py", line 188, in _authenticate_scram_sha1
res = sock_info.command(source, cmd)
File "C:\Python27\lib\site-packages\pymongo\pool.py", line 213, in command
read_concern)
File "C:\Python27\lib\site-packages\pymongo\network.py", line 99, in command
helpers._check_command_response(response_doc, None, allowable_errors)
File "C:\Python27\lib\site-packages\pymongo\helpers.py", line 196, in _check_command_response
raise OperationFailure(msg % errmsg, code, response)
OperationFailure: Authentication failed.

最佳答案

这个问题可能很老，但我遇到了同样的问题并找到了另一个可能对其他人有用的解决方案。

将 ?authSource=admin 附加到您的 MONGO_URI 变量的末尾将根据 admin 数据库而不是您正在连接的数据库验证您的凭据。

例子: app.config["MONGO_URI"] = "mongodb://username:password@host:port/db_name?authSource=admin"

关于python - 使用 flask_pymongo 时身份验证失败，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/37945262/