我从 Adam Freeman 的书“Metro Revealed:Building Windows 8 apps with XAML and C#”中派生/改编了以下代码，以在坐标已知时获取地址:

public static async Task<string> GetAddressForCoordinates(double latitude, double longitude)
{
    HttpClient httpClient = new HttpClient {BaseAddress = new Uri("http://nominatim.openstreetmap.org")};
    HttpResponseMessage httpResult = await httpClient.GetAsync(
        String.Format("reverse?format=json&lat={0}&lon={1}", latitude, longitude));
JsonObject jsonObject = JsonObject.Parse(await httpResult.Content.ReadAsStringAsync());

return jsonObject.GetNamedObject("address").GetNamedString("road");

public static async Task<string> GetCoordinatesForAddress(string address)
{
    HttpClient httpClient = new HttpClient {BaseAddress = new Uri("http://nominatim.openstreetmap.org")};
    HttpResponseMessage httpResult = await httpClient.GetAsync(
        String.Format("format=json&address={0}", address));

    JsonObject jsonObject = JsonObject.Parse(await httpResult.Content.ReadAsStringAsync());

    return jsonObject.GetNamedObject("address").GetNamedString("lat"); // <-- what about "lon"?
}

return jsonObject.GetNamedObject("address").GetNamedString("road");

return jsonObject.GetNamedObject("address").GetNamedString("lat"); // <-- what about "lon"?

var latitude jsonObject.GetNamedObject("address").GetNamedString("lat");
var longitude jsonObject.GetNamedObject("address").GetNamedString("lat");
List<string> listCoordinates = new List<string>();
listCoordinates.Add(latitude);
listCoordinates.Add(longitude);
return listCoordinates;

string latitude jsonObject.GetNamedObject("address").GetNamedString("lat");
string longtude jsonObject.GetNamedObject("address").GetNamedString("long");
return string.Format("{0};{1}", latitude, longitude);

HttpClient httpClient = new HttpClient { BaseAddress = new Uri("http://nominatim.openstreetmap.org/") };
var httpResult = await httpClient.GetAsync(
    String.Format("search?format=json&addressdetails={0}", address);

var result = await httpResult.Content.ReadAsStringAsync();
var r = (JsonArray)JsonConverter.DeserializeObject(result);//<-- JsonConvert[er] not recognized; part of Json.NET?
var latString = ((JsonValue)r[0]["lat"]).ValueType as string;
var longString = ((JsonValue)r[0]["lon"]).ValueType as string;

public static async Task`<string`> GetAddressForCoordinates(double latitude, double longitude)
{
    HttpClient httpClient = new HttpClient {BaseAddress = new Uri("http://nominatim.openstreetmap.org/")};
    HttpResponseMessage httpResult = await httpClient.GetAsync(
        String.Format("reverse?format=json&lat={0}&lon={1}", latitude, longitude));

    JsonObject jsonObject = JsonObject.Parse(await httpResult.Content.ReadAsStringAsync());

    string house = jsonObject.GetNamedObject("addressparts").GetNamedString("house");
    string road = jsonObject.GetNamedObject("addressparts").GetNamedString("road");
    string city = jsonObject.GetNamedObject("addressparts").GetNamedString("city");
    string state = jsonObject.GetNamedObject("addressparts").GetNamedString("state");
    string postcode = jsonObject.GetNamedObject("addressparts").GetNamedString("postcode");
    string country = jsonObject.GetNamedObject("addressparts").GetNamedString("country");
    return string.Format("{0} {1}, {2}, {3} {4} ({5})", house, road, city, state, postcode, country);
}

public static async Task<string> GetCoordinatesForAddress(string address)
{
    HttpClient httpClient = new HttpClient { BaseAddress = new Uri("http://nominatim.openstreetmap.org/") };
    HttpResponseMessage httpResult = await httpClient.GetAsync(
        String.Format("search?q={0}&format=json&addressdetails=1", Pluggify(address))); // In my Pluggify() method, I replace spaces with + and then lowercase it all

    var result = await httpResult.Content.ReadAsStringAsync();
    var r = (JArray)JsonConvert.DeserializeObject(result);
    var latString = ((JValue)r[0]["lat"]).Value as string;
    var longString = ((JValue)r[0]["lon"]).Value as string;
    return string.Format("{0};{1}", latString, longString);
}

// If address has not been explicitly entered, try to suss it out:
                    address = textBoxAddress1.Text.Trim();
                    lat = textBoxLatitude1.Text.Trim();
                    lng = textBoxLongitude1.Text.Trim();
                    if (string.IsNullOrWhiteSpace(address))
                    {
                        address = await SOs_Classes.SOs_Utils.GetAddressForCoordinates(lat, lng);
                    }

. . .

        public async static Task<string> GetAddressForCoordinates(string latitude, string longitude)
        {
            string currentgeoLoc = string.Format("{0},{1}", latitude, longitude);
            string queryString = string.Empty;
            string nokiaAppID = "j;dsfj;fasdkdf";
            object nokiaAppCode = "-14-14-1-7-47-178-78-4";
            var hereNetUrl = string.Format(
                "http://demo.places.nlp.nokia.com/places/v1/discover/search?at={0}&q={1}&app_id={2}    
&app_code={3}&accept=application/json",
                    currentgeoLoc, queryString, nokiaAppID, nokiaAppCode);    
            // get data from HERE.net REST API
            var httpClient = new HttpClient();
            var hereNetResponse = await httpClient.GetStringAsync(hereNetUrl);    
            // deseralize JSON from Here.net 
            using (var tr = new StringReader(hereNetResponse))
            using (var jr = new JsonTextReader(tr))
            {
                var rootObjectResponse = new JsonSerializer    
().Deserialize<JsonDOTNetHelperClasses.RootObject>(jr);    
                var firstplace = rootObjectResponse.results.items.First();
                return HtmlUtilities.ConvertToText(firstplace.vicinity);
                // NOTE: There is also a title (such as "Donut Shop", "Fire stations", etc.?) and type (such as "residence" or "business", etc.?)
            }
        }

        var firstplace = rootObjectResponse.results.items.First();

{"results":{"items":[]},"search":{"context":{"location":{"position":[38.804967,-90.113183],"address":
{"postalCode":"62048","city":"Hartford","stateCode":"IL","county":"Madison","countryCode":"USA","country":"
USA","text":"Hartford IL 62048
USA"}},"type":"urn:nlp-types:place","href":"http://demo.places.nlp.nokia.com/places/v1/places/loc-
dmVyc2lvbj0xO3RpdGxlPUhhcnRmb3JkO2xhdD0zOC44MDQ5Njc7bG9uPS05MC4xMTMxODM7Y2l0eT1IY
XJ0Zm9yZDtwb3N0YWxDb2RlPTYyMDQ4O2NvdW50cnk9VVNBO3N0YXRlQ29kZT1JTDtjb3VudHk9TWFka
XNvbjtjYXRlZ29yeUlkPWNpdHktdG93bi12aWxsYWdl;context=Zmxvdy1pZD02YmUzZDM4Yi0wNGVhLTUyM
jgtOWZmNy1kNWNkZGM0ODI5OThfMTM1NzQyMDI1NTg1M18wXzE2MA?
app_id=F6zpNc3TjnkiCLwl_Xmh&app_code=QoAM_5BaVDZvkE2jRvc0mw"}}}

最佳答案

您要问的只是“地理编码”。如果您想专门使用 Nominatim，他们称之为“搜索”。这在一定程度上是地址验证；但“验证”的一部分包括坐标(边界框、纬度/经度等；取决于搜索的内容和结果的类型)。有很多关于结果的细节，太多了，不能简单地在这里发布；但可以在此处找到此详细信息:http://wiki.openstreetmap.org/wiki/Nominatim#Search (包括考试)。
您必须解析结果(XML、JSON 或 HTML)才能获得您感兴趣的字段。
更新 1:
至于如何处理实际值:这取决于。如果您想在表单中查看坐标，只需将 lat 和 long 字符串放入单独的控件中即可。如果你想把它放在一个单独的控件中，可以使用 string.Format("{0}, {1}", latString, longString) .如果您想为 Windows 应用商店应用程序使用各种方法/类型的坐标，您可能需要使用 Microsoft.Maps.MapControl.Location类(class)。例如:

  Double latNumber;
  Double longNumber;
  if(false == Double.TryParse(latString, out latNumber)) throw new InvalidOperationException();
  if(false == Double.TryParse(longString, out longNumber)) throw new InvalidOperationException();
  var location = new Location(latNumber, longNumber);

    var httpClient = new HttpClient();
    var httpResult = await httpClient.GetAsync(
        "http://nominatim.openstreetmap.org/search?q=135+pilkington+avenue,+birmingham&format=json&polygon=1&addressdetails=1");

    var result = await httpResult.Content.ReadAsStringAsync();
    var r = (JArray) JsonConvert.DeserializeObject(result);
    var latString = ((JValue) r[0]["lat"]).Value as string;
    var longString = ((JValue)r[0]["lon"]).Value as string;

关于c# - 已知地址时如何获取坐标？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13924674/