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MySQL 错误 : Unknown column in 'where clause'

我有一个名为bank的表,其中包含三列:uid、nick、balance。我正在尝试创建一个将根据昵称返回余额的查询,但当我使用此查询时出现错误Unknowncolumn'Alex'in'whereclause':SELECTb.balanceFROMbankASbWHEREb.nick=`Alex`LIMIT1谁能看出我在这里做错了什么? 最佳答案 反引号(`)用于标识符,如表名、列名等。单引号(')用于字符串文字。你想做的:SELECTb.balanceFROMbankASbWHEREb.nick='Alex'LIMIT1或者,

mysql - 语法错误或访问冲突 : 1055 Expression #8 of SELECT list is not in GROUP BY clause and contains nonaggregated column

我尝试了CakePHP3.x“Bookmaker教程”,并按照说明一步一步地进行操作。不幸的是,在第一章结束时,我收到了附加错误:Error:SQLSTATE[42000]:Syntaxerrororaccessviolation:1055Expression#8ofSELECTlistisnotinGROUPBYclauseandcontainsnonaggregatedcolumn'wis.Tags.id'whichisnotfunctionallydependentoncolumnsinGROUPBYclause;thisisincompatiblewithsql_mode=on

mysql - 语法错误或访问冲突 : 1055 Expression #8 of SELECT list is not in GROUP BY clause and contains nonaggregated column

我尝试了CakePHP3.x“Bookmaker教程”,并按照说明一步一步地进行操作。不幸的是,在第一章结束时,我收到了附加错误:Error:SQLSTATE[42000]:Syntaxerrororaccessviolation:1055Expression#8ofSELECTlistisnotinGROUPBYclauseandcontainsnonaggregatedcolumn'wis.Tags.id'whichisnotfunctionallydependentoncolumnsinGROUPBYclause;thisisincompatiblewithsql_mode=on

mysql - 拉维尔 5.3 : Syntax error or access violation: 1463 Non-grouping field 'distance' is used in HAVING clause

这个错误是在将整个源代码移动到5.3版本后出现的,我现在挠头了两个多小时。所以我有这种Eloquent查询:POI::select('*',DB::raw("SQRT(POW((x-{$this->x}),2)+POW((y-{$this->y}),2))ASdistance"))->where('status',Config::get('app.poi_state.enabled'))->whereNotIn('id',$excludePOIList)->having('distance','orderBy('distance')->get();它在升级之前找到了,现在它抛出:Syn

mysql - 拉维尔 5.3 : Syntax error or access violation: 1463 Non-grouping field 'distance' is used in HAVING clause

这个错误是在将整个源代码移动到5.3版本后出现的,我现在挠头了两个多小时。所以我有这种Eloquent查询:POI::select('*',DB::raw("SQRT(POW((x-{$this->x}),2)+POW((y-{$this->y}),2))ASdistance"))->where('status',Config::get('app.poi_state.enabled'))->whereNotIn('id',$excludePOIList)->having('distance','orderBy('distance')->get();它在升级之前找到了,现在它抛出:Syn

php - 违反完整性约束 : 1052 Column 'id' in where clause is ambiguous

我正在做一个简单的查询,但它不起作用,我也不知道为什么。我最近开始熟悉PDO与数据库的连接。代码如下:连接是:define("HOST","localhost");define("USER","root");define("PASS","password");define("BASE","portugalforcedb");try{$conexao='mysql:host='.HOST.';dbname='.BASE;$connect=newPDO($conexao,USER,PASS);$connect->setAttribute(PDO::ATTR_ERRMODE,PDO::ERR

php - 违反完整性约束 : 1052 Column 'id' in where clause is ambiguous

我正在做一个简单的查询,但它不起作用,我也不知道为什么。我最近开始熟悉PDO与数据库的连接。代码如下:连接是:define("HOST","localhost");define("USER","root");define("PASS","password");define("BASE","portugalforcedb");try{$conexao='mysql:host='.HOST.';dbname='.BASE;$connect=newPDO($conexao,USER,PASS);$connect->setAttribute(PDO::ATTR_ERRMODE,PDO::ERR

MySQL "Unknown Column in On Clause"

这个问题在这里已经有了答案:MySQLunknowncolumninONclause(4个回答)关闭6年前。我有以下MySQL查询:SELECTposts.id,posts.name,LEFT(posts.content,400),posts.author,posts.date,users.display_name,GROUP_CONCAT(tags.tagORDERBYtag_linking.pidASCSEPARATOR",")update_tagsFROMposts,tag_linking,tagsINNERJOIN`users`ONposts.author=users.id;W

MySQL "Unknown Column in On Clause"

这个问题在这里已经有了答案:MySQLunknowncolumninONclause(4个回答)关闭6年前。我有以下MySQL查询:SELECTposts.id,posts.name,LEFT(posts.content,400),posts.author,posts.date,users.display_name,GROUP_CONCAT(tags.tagORDERBYtag_linking.pidASCSEPARATOR",")update_tagsFROMposts,tag_linking,tagsINNERJOIN`users`ONposts.author=users.id;W

mysql - 'having clause' 中的未知列

我需要在sakila数据库中找到最长的电影租借期。我试过这个:SELECTDISTINCTcustomer.first_nameFROMrental,customerWHERErental.customer_id=customer.customer_idGROUPBYrental.rental_idHAVING(rental.return_date-rental.rental_date)=(SELECTMAX(countRental)FROM(SELECT(rental.return_date-rental.rental_date)AScountRentalFROMrental,cus